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6x^2-6-13x=0
a = 6; b = -13; c = -6;
Δ = b2-4ac
Δ = -132-4·6·(-6)
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{313}}{2*6}=\frac{13-\sqrt{313}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{313}}{2*6}=\frac{13+\sqrt{313}}{12} $
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